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Bounded function

Mathematical function whose set of values is bounded

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In mathematics, a function f defined on some set X with real or complex values is called bounded if the set of its values (its image) is bounded. In other words, there exists a real number M such that

|f(x)|\leq M

for all x in X. A function that is not bounded is said to be unbounded.

If f is real-valued and f(x)\leq A for all x in X, then the function is said to be bounded (from) above by A. If f(x)\geq B for all x in X, then the function is said to be bounded (from) below by B. A real-valued function is bounded if and only if it is bounded from above and below.

An important special case is a bounded sequence, where X is taken to be the set \mathbb {N} of natural numbers. Thus a sequence f=(a_{0},a_{1},a_{2},\ldots ) is bounded if there exists a real number M such that

|a_{n}|\leq M

for every natural number n. The set of all bounded sequences forms the sequence space l^{\infty }.

The definition of boundedness can be generalized to functions f:X\rightarrow Y taking values in a more general space Y by requiring that the image f(X) is a bounded set in Y.

02Examples

  • The sine function \sin :\mathbb {R} \rightarrow \mathbb {R} is bounded since |\sin(x)|\leq 1 for all x\in \mathbb {R}.
  • The function f(x)=(x^{2}-1)^{-1}, defined for all real x except for −1 and 1, is unbounded. As x approaches −1 or 1, the values of this function get larger in magnitude. This function can be made bounded if one restricts its domain to be, for example, [2,\infty ) or (-\infty ,-2].
  • The function {\textstyle f(x)=(x^{2}+1)^{-1}, defined for all real x, is bounded, since {\textstyle |f(x)|\leq 1 for all x.
  • The inverse trigonometric function arctangent defined as: y=\arctan(x) or x=\tan(y) is increasing for all real numbers x and bounded with -{\frac {\pi }{2}}<y<{\frac {\pi }{2}} radians
  • By the boundedness theorem, every continuous function on a closed interval, such as f:[0,1]\rightarrow \mathbb {R}, is bounded. More generally, any continuous function from a compact space into a metric space is bounded.
  • All complex-valued functions f:\mathbb {C} \rightarrow \mathbb {C} which are entire are either unbounded or constant as a consequence of Liouville's theorem. In particular, the complex \sin :\mathbb {C} \rightarrow \mathbb {C} must be unbounded since it is entire.
  • The function f which takes the value 0 for x rational number and 1 for x irrational number (cf. Dirichlet function) is bounded. Thus, a function does not need to be "nice" in order to be bounded. The set of all bounded functions defined on [0,1] is much larger than the set of continuous functions on that interval. Moreover, continuous functions need not be bounded; for example, the functions g:\mathbb {R} ^{2}\to \mathbb {R} and h:(0,1)^{2}\to \mathbb {R} defined by g(x,y):=x+y and h(x,y):={\frac {1}{x+y}} are both continuous, but neither is bounded. (However, a continuous function must be bounded if its domain is both closed and bounded.)
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Sources and credits

This article is adapted from the Wikipedia article Bounded function, written by its contributors and licensed under CC BY-SA 4.0. Fathomly has changed the layout, removed citation markers, navigation and maintenance notices, and adjusted punctuation. This adapted version is shared under the same license. For references, see the original article.

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