Dirichlet function
Indicator function of rational numbers
In mathematics, the Dirichlet function is the indicator function of the set of rational numbers
over the set of real numbers
, i.e.
for a real number x if x is a rational number and
if x is not a rational number (i.e. is an irrational number).
It is named after the mathematician Peter Gustav Lejeune Dirichlet. It is an example of a pathological function which provides counterexamples to many situations.
01Topological properties
- The Dirichlet function is nowhere continuous. We can prove this by reference to the definition of a continuous function to show that it violates the continuity properties at both rational and irrational arguments:
Proof
- If y is rational, then f(y) = 1. To show the function is not continuous at y, we need to find an ε such that no matter how small we choose δ, there will be points z within δ of y such that f(z) is not within ε of f(y) = 1. In fact, 1⁄2 is such an ε. Because the irrational numbers are dense in the reals, no matter what δ we choose we can always find an irrational z within δ of y, and f(z) = 0 is at least 1⁄2 away from 1.
- If y is irrational, then f(y) = 0. Again, we can take ε = 1⁄2, and this time, because the rational numbers are dense in the reals, we can pick z to be a rational number as close to y as is required. Again, f(z) = 1 is more than 1⁄2 away from f(y) = 0.
- The Dirichlet function can be constructed as the double pointwise limit of a sequence of continuous functions, as follows:
for integer j and k. This shows that the Dirichlet function is a Baire class 2 function. It cannot be a Baire class 1 function because a Baire class 1 function can only be discontinuous on a meagre set.
02Periodicity
For any real number x and any positive rational number T, . The Dirichlet function is therefore an example of a real periodic function which is not constant but whose set of periods, the set of rational numbers, is a dense subset of
.
03Integration properties
- The Dirichlet function is not Riemann-integrable on any segment of
despite being bounded because the set of its discontinuity points is not negligible (for the Lebesgue measure).
- The Dirichlet function has both an upper Darboux integral (namely,
) and a lower Darboux integral (0) over any bounded interval
, but they are not equal if
, so the Dirichlet function is not Darboux-integrable (and therefore not Riemann-integrable) over any nondegenerate interval.
- The Dirichlet function provides a counterexample showing that the monotone convergence theorem is not true in the context of the Riemann integral.
Proof
Using an enumeration of the rational numbers between 0 and 1, we define the function fn (for all nonnegative integer n) as the indicator function of the set of the first n terms of this sequence of rational numbers. The increasing sequence of functions fn (which are nonnegative, Riemann-integrable with a vanishing integral) pointwise converges to the Dirichlet function which is not Riemann-integrable.
- The Dirichlet function is Lebesgue-integrable on
and its integral over
is zero because it is zero except on the set of rational numbers which is negligible (for the Lebesgue measure).
Sources and credits
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