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Dimension of a scheme

In algebraic geometry, the dimension of a scheme is a generalization of the dimension of an algebraic variety. Scheme theory emphasizes the relative point of view and, accordingly, the relative dimension of a morphism of schemes is also important.

01Definition

By definition, the dimension of a scheme X is the dimension of the underlying topological space: the supremum of the lengths of chains of irreducible closed subsets:

\emptyset \neq V_{0}\subsetneq V_{1}\subsetneq \cdots \subsetneq V_{\ell }\subset X.

In particular, if X=\operatorname {Spec} A is an affine scheme, then such chains correspond to chains of prime ideals (inclusion reversed), so the dimension of X is precisely the Krull dimension of A.

If Y is an irreducible closed subset of a scheme X, then the codimension of Y in X is the supremum of the lengths of chains of irreducible closed subsets:

Y=V_{0}\subsetneq V_{1}\subsetneq \cdots \subsetneq V_{\ell }\subset X.

An irreducible subset of X is an irreducible component of X if and only if its codimension in X is zero. If X=\operatorname {Spec} A is affine, then the codimension of Y in X is precisely the height of the prime ideal defining Y in X.

02Examples

  • If a finite-dimensional vector space V over a field is viewed as a scheme over the field, then the dimension of the scheme V is the same as the vector-space dimension of V.
  • Let X=\operatorname {Spec} k[x,y,z]/(xy,xz), k a field. Then it has dimension 2 (since it contains the hyperplane H=\{x=0\}\subset \mathbb {A} ^{3} as an irreducible component). If x is a closed point of X, then \operatorname {codim} (x,X) is 2 if x lies in H and is 1 if it is in X-H. Thus, \operatorname {codim} (x,X) for closed points x can vary.
  • Let X be an algebraic pre-variety; i.e., an integral scheme of finite type over a field k. Then the dimension of X is the transcendence degree of the function field k(X) of X over k. Also, if U is a nonempty open subset of X, then \dim U=\dim X.
  • Let R be a discrete valuation ring and X=\mathbb {A} _{R}^{1}=\operatorname {Spec} (R[t]) the affine line over it. Let \pi :X\to \operatorname {Spec} R be the projection. \operatorname {Spec} (R)=\{s,\eta \} consists of 2 points, s corresponding to the maximal ideal and closed and \eta the zero ideal and open. Then the fibers \pi ^{-1}(s),\pi ^{-1}(\eta ) are closed and open, respectively. We note that \pi ^{-1}(\eta ) has dimension one, while X has dimension 2=1+\dim R and \pi ^{-1}(\eta ) is dense in X. Thus, the dimension of the closure of an open subset can be strictly bigger than that of the open set.
  • Continuing the same example, let {\mathfrak {m}}_{R} be the maximal ideal of R and \omega _{R} a generator. We note that R[t] has height-two and height-one maximal ideals; namely, {\mathfrak {p}}_{1}=(\omega _{R}t-1) and {\mathfrak {p}}_{2}= the kernel of R[t]\to R/{\mathfrak {m}}_{R},f\mapsto f(0){\bmod {\mathfrak {m}}}_{R}. The first ideal {\mathfrak {p}}_{1} is maximal since R[t]/(\omega _{R}t-1)=R[\omega _{R}^{-1}]= the field of fractions of R. Also, {\mathfrak {p}}_{1} has height one by Krull's principal ideal theorem and {\mathfrak {p}}_{2} has height two since {\mathfrak {m}}_{R}[t]\subsetneq {\mathfrak {p}}_{2}. Consequently,
\operatorname {codim} ({\mathfrak {p}}_{1},X)=1,\,\operatorname {codim} ({\mathfrak {p}}_{2},X)=2,
while X is irreducible.

03Equidimensional scheme

An equidimensional scheme (or, pure dimensional scheme) is a scheme whose irreducible components are of the same dimension (implicitly assuming the dimensions are all well-defined).

Examples

All irreducible schemes are equidimensional.

In an affine space, the union of a line and a point not on the line is not equidimensional. Generally, if two closed subschemes of some scheme, neither containing the other, have unequal dimensions, then their union is not equidimensional.

If a scheme is smooth (for instance, étale) over Spec k for some field k, then every connected component (which is then, in fact, an irreducible component) is equidimensional.

04Relative dimension

Let f:X\rightarrow Y be a morphism locally of finite type between two schemes X and Y. The relative dimension of f at a point y\in Y is the dimension of the fiber f^{-1}(y). If all the nonempty fibers are purely of the same dimension n, then one says that f is of relative dimension n.

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Sources and credits

This article is adapted from the Wikipedia article Dimension of a scheme, written by its contributors and licensed under CC BY-SA 4.0. Fathomly has changed the layout, removed citation markers, navigation and maintenance notices, and adjusted punctuation. This adapted version is shared under the same license. For references, see the original article.

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